A little intuition.
A better solution.
for i, number in enumerate(nums):
needed = target - number
if needed in seen:
return [seen[needed], i]
01 / WEB DEVELOPMENT
PatternForge
Learn the pattern.
Build the intuition.
A coding-interview trainer that connects guided explanations, runnable code, and visual walkthroughs in one learning experience.
- Python and JavaScript exercises in the browser
- Step-by-step algorithm visualizations
- Locally saved progress and spaced review




